SOLUTION: In the problem, solve the equation on the interval 0 is greater than or equal to theta is greater than 2 pie.
sin theta= square root of 2 divided by 2
Algebra ->
Trigonometry-basics
-> SOLUTION: In the problem, solve the equation on the interval 0 is greater than or equal to theta is greater than 2 pie.
sin theta= square root of 2 divided by 2
Log On
Question 517984: In the problem, solve the equation on the interval 0 is greater than or equal to theta is greater than 2 pie.
sin theta= square root of 2 divided by 2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve the equation on the interval 0 is <= x <= 2(pi).
sin theta= [square root of 2] divided by [2]
---
sin^-1(sqrt(2)/2) = pi/4 or (3/4)pi
=======================================
Cheers,
Stan H.
==============
(