SOLUTION: find four consecutive intergers such that twice the first subtracted from the sum of the other three intergers is 16.

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Question 517957: find four consecutive intergers such that twice the first subtracted from the sum of the other three intergers is 16.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+1, X+2, & X+3 be the 4 integers.
(X+1)+(X+2)+(X+3)-2X=16
3X+6-2X=16
X+6=16
X=16-6
X=10 ANS.
PROOF:
(10+1)+(10+2)+(10+3)-2*10=16
11+12+13-20=16
36-20=16
16=16