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Question 517794: find the vertex x and y intercept of the parabola given by the equation y=3x^2-2x+1
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! find the vertex x and y intercept of the parabola given by the equation y=3x^2-2x+1
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y=3x^2-2x+1
y-intercept
set x=0
y=0-0+1=1
y-intercept=1
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y=3x^2-2x+1
complete the square
y=3(x^2-2x/3+1/9)+1-1/3
y=3(x-1/3)^2+2/3
vertex: (1/3,2/3)
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Since the minimum point on the curve is 2/3, there is no crossing of the x-axis, thus, there are no x-intercepts
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