SOLUTION: The width of a rectangle is three digits shorter than its length. The area is 180 square digits. find the length and width
This is what I have so far....
x sqared -3x-180=0
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-> SOLUTION: The width of a rectangle is three digits shorter than its length. The area is 180 square digits. find the length and width
This is what I have so far....
x sqared -3x-180=0
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Question 517758: The width of a rectangle is three digits shorter than its length. The area is 180 square digits. find the length and width
This is what I have so far....
x sqared -3x-180=0
what do I do next Answer by deborabr(181) (Show Source):
You can put this solution on YOUR website! x^2-3x-180=0
(-3)^2-4(1)(-180)
9+720=729 -> delta
x=[-(-3)+/- root 729]/2*1
x=[3 +/- 27]/2
x'= [3+27]/2 x'=30/2 x'=15
x"= [3-27]/2 x"=-24/2 x"=-12
answer x'=15 and x"=-12
