SOLUTION: two cyclists one averaging 9mph and another cyclist averaging 11 mph, start from the same place at the same time. If they travel in opposite directions, after how long will they be
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Question 517725: two cyclists one averaging 9mph and another cyclist averaging 11 mph, start from the same place at the same time. If they travel in opposite directions, after how long will they be 100 miles apart? Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Cyclists A Data
==========
Speed = 9mph
Time=t hour
Distance Covered by Cyclists A=9*t
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Cyclists B Data
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Speed = 11mph
Time=t hour
Distance covered by Cyclists B=11*t
Distance Covered by Cyclists A + Distance Covered by Cyclists B = Total Distnace apart
9t+11t=100
20t=100
20t/20=100/20
t=5 hour
They will be 100 miles apart after 5 hours.
Check
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Cyclists A Data
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Speed = 9mph
Time=5 hour
Distance Covered by Cyclists A=9*5=45 miles
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Cyclists B Data
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Speed = 11mph
Time=5 hour
Distance covered by Cyclists B=11*5=55
Cyclists A Travel + Cyclists B Travel = Total distance between two cyclists
45+55=100
100=100
