SOLUTION: How do u make 3 over (x+7) and 4 over (x-8) have common denominators the problem is. 3/(x+7) + 4/(x-8)

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Question 517495: How do u make 3 over (x+7) and 4 over (x-8) have common denominators the problem is. 3/(x+7) + 4/(x-8)
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
+3%2F%28x%2B7%29+%2B+4%2F%28x-8%29+
.
First consider the equivalent form:
.
+a%2Fb+%2B+c%2Fd+=+%28ad%2Bbc%29%2Fbd+
.
Then substitute.
.
+a+=+3+
+b+=+%28x%2B7%29+
+c+=+4+
+d+=+%28x-8%29+
.