SOLUTION: at 10 am a car leaves a house at a rate of 60 mi/h. At the same time, another car leaves the same house at a rate of 50 mi/h in the opposite direction. At what time will the cars

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Question 517404: at 10 am a car leaves a house at a rate of 60 mi/h. At the same time, another car leaves the same house at a rate of 50 mi/h in the opposite direction. At what time will the cars be 333 miles apart?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You can think of this as one car standing still
and the other moving at the sum of their speeds.
I'll say the 50 mi/hr car is standing still.
+d+=+r%2At
+333+=+%28+60+%2B+50+%29%2At+
+333+=+110t+
+t+=+333%2F110+
+t+=+3.0273+ hrs
10 AM + 3hrs = 1 PM
+.0273%2A60+=+1.636+
+.636%2A60+=+38+
They will be 333 mi apart at 1:01:38 PM