SOLUTION: Part of a $36,000 investment earns 6.5% annual interest and the rest earns 4%. If the annual interest from both is $1715, how much is invested at the 6.5% rate?

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Part of a $36,000 investment earns 6.5% annual interest and the rest earns 4%. If the annual interest from both is $1715, how much is invested at the 6.5% rate?      Log On

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Question 517312: Part of a $36,000 investment earns 6.5% annual interest and the rest earns 4%. If the annual interest from both is $1715, how much is invested at the 6.5% rate?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Part of a $36,000 investment earns 6.5% annual interest and the rest earns 4%. If the annual interest from both is $1715, how much is invested at the 6.5% rate?
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Interest + Interest = Interest
0.065x + 0.04(36000-x) = 1715
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Multiply thru by 1000 to get:
65x + 40*36000 - 40x = 1715000
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25x = 275000
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x = $11,000 (amt invested at 6.5%
36000-11000 = $25000 (amt invested at 4%
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Cheers,
Stan H.
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