|
Question 516823: what is (-1,-2) perpendicular to 2x + 3y = 0
Answer by Maths68(1474)   (Show Source):
You can put this solution on YOUR website! Given
Point (x, y)=(-1,-2)
Line:
2x+3y=0
Rearrange above equation
3y=-2x
3y/3=-2x/3
y=(-2/3)x
Compare above equation with the equation of line slope-intercept form
y=mx+b
y=(-2/3)x
m=-2/3 and b=0
Slope of the given line m = -2/3 and y-intercept = b = 0
Since required line is perpendicular, the multiplication of the slopes of both lines result in (-1), therefore the slope of the required line will be (3/2)
================================================================
Now we have a point (-1,-2) and slope (3/2) of the required line we can easily find the required line put these values in the equation of slope-intercept form to find the y-intercept of the required line
y=mx+b
-2=(3/2)(-1)+b
-2=-3/2+b
-2+3/2=+b
(-4+3)/2=b
b=-1/2
y-intercept of the required line =b=-1/2
================================================================
Put the values of ‘m’ and ‘b’ in equation of the line slope-intercept form
y=mx+b
y=(3/2)x-1/2
Above equation is the required equation of the line in slope-intercept form.
|
|
|
| |
