SOLUTION: I have the answer in the back of the book. Still having trouble getting there. 4^2/3 * 6^2/3 * 9^2/3 Have tried squaring 4 and then taking the cubed root but don't get good n

Algebra ->  Square-cubic-other-roots -> SOLUTION: I have the answer in the back of the book. Still having trouble getting there. 4^2/3 * 6^2/3 * 9^2/3 Have tried squaring 4 and then taking the cubed root but don't get good n      Log On


   

Question 51682This question is from textbook
: I have the answer in the back of the book. Still having trouble getting there.
4^2/3 * 6^2/3 * 9^2/3
Have tried squaring 4 and then taking the cubed root but don't get good numbers.
The book says answer is 36????? This question is from textbook

Found 3 solutions by mathchemprofessor, gsmani_iyer, MathTherapy:
Answer by mathchemprofessor(65) About Me  (Show Source):
You can put this solution on YOUR website!
4^2/3 * 6^2/3 * 9^2/3=(4^2)^(1/3)*(6^2)^(1/3)*(9^2)^(1/3)
=(16)^(1/3)*(36)^(1/3)*(81)^(1/3)
-(16*36*81)^(1/3)=(46656)^(1/3)=(36^3)^(1/3)=36

Answer by gsmani_iyer(201) About Me  (Show Source):
You can put this solution on YOUR website!

4%5E%282%2F3%296%5E%282%2F3%299%5E%282%2F3%29
= 3rd+sqrt%284%5E2%29%2A3rd+sqrt%286%5E2%29%2A3rd+sqrt%289%5E2%29
= 3rd+sqrt%2816%29%2A3rd+sqrt%2836%29%2A3rd+sqrt%2881%29
= 3rd sqrt%2816%2A36%2A81%29
= 3rd sqrt%2846656%29 = 3rdsqrt%2827%2A27%2A64%29 = 3rdsqrt%283%5E3%2A3%5E3%2A4%5E3%29
= 3 * 3 * 4 = 36. Answer. I hope this must have solved your trouble in getting the answer.
Note: Read 3rd as 3rd root in the above solution.

gsm

Answer by MathTherapy(10704) About Me  (Show Source):
You can put this solution on YOUR website!
I have the answer in the back of the book. Still having trouble getting there.

4^2/3 * 6^2/3 * 9^2/3

Have tried squaring 4 and then taking the cubed root but don't get good numbers.

The book says answer is 36?????
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