SOLUTION: A train leaves Lexington for Indianapolis, 200 miles away, at 2:00 PM and averages 60 miles per hour. A second train traveling on an adjacent track leaves Indianapolis for Lexingto
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Question 516665: A train leaves Lexington for Indianapolis, 200 miles away, at 2:00 PM and averages 60 miles per hour. A second train traveling on an adjacent track leaves Indianapolis for Lexington at 4:30 PM and averages 40 miles per hour. At what time will the trains meet? (Round to the nearest minute.) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A train leaves Lexington for Indianapolis, 200 miles away, at 2:00 PM and averages 60 miles per hour.
A second train traveling on an adjacent track leaves Indianapolis for Lexington at 4:30 PM and averages 40 miles per hour.
At what time will the trains meet? (Round to the nearest minute.)
:
Let t = travel time of the Ind/Lex train (2nd train)
then
(t+2.5) = travel time of the Lex/Ind train (1st train)
:
When they meet their travel distances will total 200 mi
Write a distance equation: dist = speed * time
:
60(t+2.5) + 40t = 200
60t + 150 + 40t = 200
60t + 40t = 200 - 150
100t = 50
t =
t = .5 hrs which is 30 minutes. They meet at 5 PM
;
:
Check this, find the dist each traveled. (1st train travel time: 2.5+.5 = 3 hrs)
60(3) = 180
40(.5)= 20
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total: 200 mi
