SOLUTION: @ noon a train leaves bridgton heading east at 90 mi/h to cogsville, 450 mi away. at 12:15 p.m. a train leave cogsville heading west to bridgton at 100 mi/h. at what time will they

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Question 51645: @ noon a train leaves bridgton heading east at 90 mi/h to cogsville, 450 mi away. at 12:15 p.m. a train leave cogsville heading west to bridgton at 100 mi/h. at what time will they pass each other?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Where will the 1st train be at 12:15?
It will have travelled for 15 min at 90 mi/hr
r*t = d
90 mi/hr * 1/4 hr = 22.5 mi from Bridgton
Now it is (450 - 22.5) mi from Cogsville
Now the 2nd train leaves, and both will travel for the same
amount of time until they meet
t%281%29+=+t%282%29
d%281%29%2Fr%281%29+=+d%282%29+%2F+r%282%29
d%281%29+%2F+90+=+d%282%29+%2F+100
d%281%29+=+.9%2Ad%282%29
d%281%29+%2B+d%282%29+=+450+-+22.5
d%281%29+%2B+d%282%29+=+427.5
.9%2Ad%282%29+%2B+d%282%29+=+427.5
1.9%2Ad%282%29+=+427.5
d%282%29+=+225
d%281%29+=+427.5+-+225
d%281%29+=+202.5
t%281%29+=+t%282%29
202.5+%2F+90+=+225+%2F+100
2.25+=+2.25
So, the trains travel for 2.25 hours until they meet. That is with
a starting time of 12:15 pm
So, they meet at 12:15 pm + 2 1/4 hrs = 2:30 pm