SOLUTION: A car left seattle traveling 45mph. A second car left from the same place one hour later on the same road traveling 60mph. How long will it take the second car to catch up with the
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Question 516334: A car left seattle traveling 45mph. A second car left from the same place one hour later on the same road traveling 60mph. How long will it take the second car to catch up with the first car. Which of these is the correct second eqaution for the problem? Found 2 solutions by Maths68, Alan3354:Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! A car left seattle traveling 45mph. A second car left from the same place one hour later on the same road traveling 60mph. How long will it take the second car to catch up with the first car. Which of these is the correct second eqaution for the problem?
Car A Data
==========
Speed = 45mph
Time = t hour
Distance covered = x miles
Distance = speed*time
x=45*t
x=45t.............(1)
Car B Data
==========
Speed = 60mph
Time =t-1(hour)
Distance covered = x
Distance = Speed * time
x=60*(t-1)
Both cars will cover same distance
45t=60*(t-1)
45t=60t-60
45t-60t=60
-15t=-60
-15t/-15=-60/-15
t=4 hours
Car A travel time 4 hours and Car B travel time 3 hours.
After 3 hours of leaving same place Car B will catch Car A
Check
========
Car A Data
==========
Speed = 45mph
Time = 4 hour
Distance covered = x miles
Distance = speed*time
x=45*4
x=180 miles
Car B Data
==========
Speed = 60mph
Time =t-1=4-1=3(hour)
Distance covered = x
Distance = Speed * time
x=60*3
x=180 miles
You can put this solution on YOUR website! A car left seattle traveling 45mph. A second car left from the same place one hour later on the same road traveling 60mph. How long will it take the second car to catch up with the first car. Which of these is the correct second eqaution for the problem?
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The 1st car is 45 miles ahead when the 2nd car starts.
The 2nd car gains on the 1st at 15 mi/hr (60-45)
45/15 = 3 hours to catch up.
