SOLUTION: A girl and boy are playing a game that consists of ten different numbered cards that are face down on a table. The faces of the cards are labeled using the numerals 1-10 (each card
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-> SOLUTION: A girl and boy are playing a game that consists of ten different numbered cards that are face down on a table. The faces of the cards are labeled using the numerals 1-10 (each card
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Question 516297: A girl and boy are playing a game that consists of ten different numbered cards that are face down on a table. The faces of the cards are labeled using the numerals 1-10 (each card is numbered differently). If each person turns over a different card, what is the probability that the sum of the two cards is even? Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! A girl and boy are playing a game that consists of ten different numbered cards that are face down on a table. The faces of the cards are labeled using the numerals 1-10 (each card is numbered differently). If each person turns over a different card, what is the probability that the sum of the two cards is even?
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The sum will be even if either both are even or both are odd.
The probability that both cards are odd is:
P(both odd) = 5/10*4/9 = 20/90
The probability that both are even is:
P(both even) = 5/10*4/9 = 20/90
So the total probability that the sum is even is the sum of the individual probabilities:
P(sum even) = 20/90 + 20/90 = 4/9
