SOLUTION: How do I solve problems like |3x| + 4 < 34? I've tried this first to get two solutions. |3x| + 4 < 34 and |3x| + 4 < -34. Then I subtracted 4 from both sides to get 3x < 30 and 3x

Algebra ->  Absolute-value -> SOLUTION: How do I solve problems like |3x| + 4 < 34? I've tried this first to get two solutions. |3x| + 4 < 34 and |3x| + 4 < -34. Then I subtracted 4 from both sides to get 3x < 30 and 3x       Log On


   

Question 515916: How do I solve problems like |3x| + 4 < 34? I've tried this first to get two solutions. |3x| + 4 < 34 and |3x| + 4 < -34. Then I subtracted 4 from both sides to get 3x < 30 and 3x < -38. The solutions that I arrived at were x < 10 and x < -38/3. Is this correct?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do I solve problems like |3x| + 4 < 34? I've tried this first to get two solutions. |3x| + 4 < 34 and |3x| + 4 < -34. Then I subtracted 4 from both sides to get 3x < 30 and 3x < -38. The solutions that I arrived at were x < 10 and x < -38/3. Is this correct
**
for 3x>0
3x+4<-34
3x<-38
x<-38/3
..
for 3x<
-3x+4<-34
-3x<-38
divide by -3 and reverse inequality sign
x>38/3
solution:
(-∞,-38/3) U (38/3, ∞)
note:To find both solutions you only need to change the sign inside the absolute bars.