SOLUTION: A tank contains 8000L of a solution that is 40%acid. How much water should be added to make a solution that is 30% acid?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A tank contains 8000L of a solution that is 40%acid. How much water should be added to make a solution that is 30% acid?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 515695: A tank contains 8000L of a solution that is 40%acid. How much water should be
added to make a solution that is 30% acid?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A tank contains 8000L of a solution that is 40%acid. How much water should be
added to make a solution that is 30% acid?
.
Let x = amount (liters) of water to add
then
.40(8000) = .30(8000+x)
3200 = 2400+.30x
800 = .30x
2666.67 liters = x