SOLUTION: I am having trouble trying to solve this problem. Would someobdy be able to assist me? Solve - 3x^2 - 7x - 5 = 0 a. The solutions(s) is/are x=? b. Find the x-intercepts of

Algebra ->  Rational-functions -> SOLUTION: I am having trouble trying to solve this problem. Would someobdy be able to assist me? Solve - 3x^2 - 7x - 5 = 0 a. The solutions(s) is/are x=? b. Find the x-intercepts of       Log On


   



Question 515573: I am having trouble trying to solve this problem. Would someobdy be able to assist me?
Solve - 3x^2 - 7x - 5 = 0
a. The solutions(s) is/are x=?
b. Find the x-intercepts of f(x) = 3x^2 -7x - 5.
1/3 x 3x^2 - 7/3x - 5/3 = 0
x^2 - 7/3x - 5/3 = 0
x^2 - 7/3x - 5/3 this is where I get lost.
Thank you.
Sincerely,
Christine Fitzgerald

Found 2 solutions by drcole, Alan3354:
Answer by drcole(72) About Me  (Show Source):
You can put this solution on YOUR website!
You are given the quadratic equation
-3x%5E2+-+7x+-+5+=+0
It looks like you are trying to factor this quadratic, but the easiest way to solve this one is to use the quadratic formula: recall that the solutions to
ax%5E2+%2B+bx+%2B+c+=+0
are
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Here, a = -3, b = -7, and c = -5, so we substitute in and get:

x+=+%287+%2B-+sqrt%28+49+-+60+%29%29%2F%28-6%29+ (simplifying)
x+=+%287+%2B-+sqrt%28-11%29%29%2F%28-6%29+ (simplifying)
+x+=+%287+%2B-+i%2A+sqrt%2811%29%29%2F%28-6%29+ (since sqrt%28-11%29+=+sqrt%28-1%29%2Asqrt%2811%29+=+i%2Asqrt%2811%29)
So the two solutions are:
x+=+%287+%2B+i+%2A+sqrt%2811%29%29%2F%28-6%29+=+%28-7+-+i+%2A+sqrt%2811%29%29%2F%286%29
and
x+=+%287+-+i+%2A+sqrt%2811%29%29%2F%28-6%29+=+%28-7+%2B+i+%2A+sqrt%2811%29%29%2F%286%29
Now, the x-intercepts of the graph of f%28x%29+=+ax%5E2+%2B+bx+%2B+c are the REAL roots of ax%5E2+%2B+bx+%2Bc+=+0. If the quadratic equation has no real roots, then the graph never intersects the x-axis: it is either always above the x-axis, or always below it. In this case, the solution to the quadratic equation are non-real complex numbers, so there are no x-intercepts of f(x).

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the x-intercepts of f(x) = 3x^2 -7x - 5.
1/3 x 3x^2 - 7/3x - 5/3 = 0
x^2 - 7/3x - 5/3 = 0
x^2 - 7/3x - 5/3 this is where I get lost.
Add 5/3 to both sides
x^2 - 7/3x = 5/3
To complete the square, you have to add c, which is (b/2a)^2
c+=+%28%28-7%2F3%29%2F2%29%5E2
c = 49/36
Add that to both sides
x%5E2+-+7%2F3x+%2B+49%2F36+=+5%2F3+%2B+49%2F36+=+109%2F36
Now, %28x+-+7%2F6%29%5E2+=+109%2F36
x+-+7%2F6+=+sqrt%28109%29%2F6
x+=+7%2F6+%2B+sqrt%28109%29%2F6
x+=+7%2F6+-+sqrt%28109%29%2F6
----------------------------
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 3x%5E2%2B-7x%2B-5+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-7%29%5E2-4%2A3%2A-5=109.

Discriminant d=109 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--7%2B-sqrt%28+109+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-7%29%2Bsqrt%28+109+%29%29%2F2%5C3+=+2.90671775148509
x%5B2%5D+=+%28-%28-7%29-sqrt%28+109+%29%29%2F2%5C3+=+-0.573384418151758

Quadratic expression 3x%5E2%2B-7x%2B-5 can be factored:
3x%5E2%2B-7x%2B-5+=+%28x-2.90671775148509%29%2A%28x--0.573384418151758%29
Again, the answer is: 2.90671775148509, -0.573384418151758. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B-7%2Ax%2B-5+%29

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The other tutor used -3 for the x^2 term.