Question 515534: Paul has $3.05 in nickels and dimes. He has ten more nickels than dimes. How many of each coin does he have? Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! n = number of nickels
5n = value of nickels in cents
d = number of dimes
10d = value of dimes in cents
.
5n + 10d = 305 cents
.
n = d+10
.
substitute
.
5(d+10) + 10d = 305
.
5d +50 +10d = 305
.
15d = 255
.
d = 255/15 = 17
.
n = d+10 = 27
.
Check the values to be sure this is the answer.
.
5(17) = 85
10(27) = 270
85 + 270 = 355
Correct
.
Answer: He has 17 dimes and 27 nickels.
.
Done.
(