SOLUTION: Find the LCM of (9+7r), (81-49r^2), and (9-7r) Thanks, Dee

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Question 515185: Find the LCM of (9+7r), (81-49r^2), and (9-7r)
Thanks,
Dee

Answer by drcole(72) About Me  (Show Source):
You can put this solution on YOUR website!
To find the least common multiple, we need to first factor each of the expressions. The first, 9+%2B+7r, and the third, 9+-+7r, cannot be factored, but the second, 81+-+49r%5E2, is the difference of two squares:
+81+=+9%5E2 and 49r%5E2+=+7%2A7%2Ar%2Ar+=+7%2Ar%2A7%2Ar+=+%287r%29%287r%29+=+%287r%29%5E2
Remembering that every difference of two squares a%5E2+-+b%5E2 can be factored as:
a%5E2+-+b%5E2+=+%28a+%2B+b%29%28a+-+b%29
we get that
81+-+49r%5E2+=+%289+%2B+7r%29%289+-+7r%29
So we are trying to find the least common multiple of 9+%2B+7r, %289+%2B+7r%29%289+-+7r%29, and 9+-+7r. The least common multiple of three expressions A, B, and C is the simplest expression that contains A, B, and C in its factorization. So the least common multiple has to contain at least one 9+%2B+7r and one 9+-+7r in its factorization, since those appear in A and C. Do we need anything else? No, because 81+-+49r%5E2+=+%289+%2B+7r%29%289+-+7r%29, so 81+-+49r%5E2 doesn't add any new factors to the least common multiple. So the least common multiple must be %289+%2B+7r%29%289+-+7r%29 or 81+-+49r%5E2.