SOLUTION: What is the slope of a line perpendicular to 6x = 3y + 5

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Question 515182: What is the slope of a line perpendicular to 6x = 3y + 5
Found 2 solutions by oberobic, mananth:
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Get the equation into slope-intercept form: y = mx+b
.
6x = 3y +5
3y + 5 = 6x
3y = 6x -5
y = 2x - 5/3
.
A perpendicular line will have a slope that is the inverse reciprocal of 2, which = -1/2.
Let's say it's: y = -1/2x
.
+graph%28500%2C500%2C-5%2C5%2C-5%2C5%2C2%2Ax-5%2F3%2C-1%2F2%2Ax%29+

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
6 x -3 y = 5
Find the slope of this line

-3 y = -6 x + 5
Divide by -3
y = 2 x -1.67
Compare this equation with y=mx+b
slope m = 2

The slope of a line perpendicular to the above line will be the negative reciprocal
m1*m2=-1
The slope of the required line will be -1/2