Question 515145: Find the vertex, line of symmetry, and maximum or minimum value of f(x)1/5(x+1)^2+1
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertex, line of symmetry, and maximum or minimum value of f(x)1/5(x+1)^2+1
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f(x)=1/5(x+1)^2+1
This is an equation of a parabola which opens upwards of the standard form:
y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
For given equation: f(x)=1/5(x+1)^2+1
Vertex:(-1, 1)
Line of symmetry: x=-1
Since parabola opens upwards it has a minimum at 1
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