Question 515032: I'm not sure what the answer to this is;
Solve the system by substitution
x+2y=3
4x-y=-6
Answer by Maths68(1474)   (Show Source):
You can put this solution on YOUR website! By subtitutio Method
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x+2y=3.........(1)
4x-y=-6.........(2)
Take (1)
x+2y=3
x=3-2y
Put the above value of x in (2)
4x-y=-6
4(3-2y)-y=-6
12-8y-y=-6
-9y=-6-12
-9y=-18
-9y/-9=-18/-9
y=2
Put the value of y (2)
4x-y=-6
4x-2=-6
4x=-6+2
4x=-4
4x/4=-4/4
x=-1
x,y = -1, 2
Check put the valud of x and y in (1)
x+2y=3.........(1)
(-1)+2(2)=3
-1+4=3
3=3
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