SOLUTION: three years ago father was 7 times as old as his son three year hence the fathers age would be 4 times that of his son what is the present age of his father
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Question 514928: three years ago father was 7 times as old as his son three year hence the fathers age would be 4 times that of his son what is the present age of his father Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! three years ago father was 7 times as old as his son three year hence the fathers age would be 4 times that of his son what is the present age of his father
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let x=father's present age
let y=son's age 3 yrs ago
..
3 years ago:
father's age=(x-3)
(x-3)/y=7
..
3 years hence:
father's age=(x+3)
son's age=(y+6)
(x+3)/(y+6)=4
..
Equations:
x-3=7y
x+3=4(y+6)=4y+24
x-21=4y
18=3y
y=6
x=7y+3=42+3=45
ans:
present age of father=45
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