SOLUTION: The perimeter of a triangle is 72. The first side is 10 more than the second side.the third side is half of the first triangle. Find the length of each side. Please help I've done

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Question 514766: The perimeter of a triangle is 72. The first side is 10 more than the second side.the third side is half of the first triangle. Find the length of each side. Please help I've done this so many times!
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Let x, y and z be the lengths of the three sides (first, second, and third respectively)

x+y+z = 72

x+y+(1/2)x = 72

(y+10)+y+(1/2)(y+10) = 72

y+10+y+(1/2)y+5 = 72

(5/2)y+15=72

(5/2)y=72-15

(5/2)y=57

5y=57*2

5y=114

y=114/5

Now use this value of y to solve the equations
x = y+10
z = (1/2)x
to find the lengths of the other 2 sides

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The perimeter of a triangle is 72. The first side is 10 more than the second side.the third side is half of the first triangle.
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2nd side : 2x
1st side : 2x + 10
3rd side : x
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Equation:
2x + 2x+10 + x = 72
5x + 10 = 72
5x = 62
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2nd: x = 12.4
1st: 2x = 24.8
3rd: 2x+10 = 34.8
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Cheers,
Stan H.
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