SOLUTION: Determine whether or not the equation has a circle in it's graph 4x^2+4y^2-24x-40y+36=0

Algebra ->  Coordinate-system -> SOLUTION: Determine whether or not the equation has a circle in it's graph 4x^2+4y^2-24x-40y+36=0      Log On


   



Question 514401: Determine whether or not the equation has a circle in it's graph
4x^2+4y^2-24x-40y+36=0

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Determine whether or not the equation has a circle in it's graph
4x^2+4y^2-24x-40y+36=0
----
Divide thru by 4 to get:
x^2-6x + y^2-10y = -36
---
Complete the square on the x and on the y terms:
x^2-6x+9 + y^2-10y+25 = -36+9+25
-----
(x-3)^2 + (y-5)^2 = -2
-----
Not a circle because radius would be sqrt(-2) = i*sqrt(2)
===========================================================
Cheers,
Stan H.
=========