SOLUTION: y &#8804; ax+b when (a<0) Solve for x.

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Question 514247: y ≤ ax+b when (a<0) Solve for x.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
y ≤ ax+b when (a<0) Solve for x.
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y≤-ax+b
y-b≤-ax
-x≥(y-b)/a
multiply both sides by (-1) and reverse inequality sign
x≤-(y-b)/a
x≤(b-y)/a