SOLUTION: the length of a rectangle is 12cm more than its width. A second rectangle is 3cm shorter in width and 5cm longer in length than the first rectanlge and has a perimeter of 68cm. Wha

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: the length of a rectangle is 12cm more than its width. A second rectangle is 3cm shorter in width and 5cm longer in length than the first rectanlge and has a perimeter of 68cm. Wha      Log On

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Question 513800: the length of a rectangle is 12cm more than its width. A second rectangle is 3cm shorter in width and 5cm longer in length than the first rectanlge and has a perimeter of 68cm. What are the dimensions of the second rectanlge?
Answer by solver91311(24713) About Me  (Show Source):
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Let represent the measure of the width of the first rectangle. Then is the measure of the length of the first rectangle, is the measure of the width of the second rectangle, and is the measure of the length of the first rectangle.

The perimeter of a rectangle is given by two times the length plus two times the width, hence:



Solve for , then calculate and

John

My calculator said it, I believe it, that settles it
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