Question 513636: the width of a rectangle is 12 units less than length. the perimeter is 108 units. find the length Answer by umail08(87) (Show Source):
You can put this solution on YOUR website! Let: L=Length and W=Width
Perimeter = 2L + 2W
W = L – 12 … width 12 units less than length
108 = 2L + 2(L-12)
108 =2L + 2L - 24
108 = 4L - 24
108 + 24 = 4L -24 + 24
132 = 4L
132/4 = 4L/4
33 = L