Question 513562: 1.) sin < 0, tan < 0, what quadrant will both be in?
2.) Find the exact value of tan theta, given that sin theta = -1/6 and theta is in quadrant IV.
tan theta = ???
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! 1.) sin < 0, tan < 0, what quadrant will both be in?
2.) Find the exact value of tan theta, given that sin theta = -1/6 and theta is in quadrant IV.
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1.) sin<0 in quadrants III and IV. tan<0 in quadrants II and IV.
Therefore, sin and tan will be in quadrant IV
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2.) sinx=-1/6=opposite side/hypotenuse
by Pythagorean Theorem, adjacent side=√(6^2-1)=√(36-1)=√35
tanx=opposite side/adjacent side=-1/√35=-√35/35
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