SOLUTION: This one is too hard and I can't get it. . .
Find the exact value of:
'
cos ( tan^-1 (4/3) + cos^-1 (12/13 ) )
'
Thank You
Algebra ->
Trigonometry-basics
-> SOLUTION: This one is too hard and I can't get it. . .
Find the exact value of:
'
cos ( tan^-1 (4/3) + cos^-1 (12/13 ) )
'
Thank You
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Question 513523: This one is too hard and I can't get it. . .
Find the exact value of:
'
cos ( tan^-1 (4/3) + cos^-1 (12/13 ) )
'
Thank You Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the exact value of:
cos ( tan^-1 (4/3) + cos^-1 (12/13 ) )
**
(tan^-1 (4/3) = angle whose tan=4/3
This means you are working with a 3-4-5 right triangle
cos of this angle, then, =adjacent/hypotenuse=3/5
..
cos^-1 (12/13=angle whose cos=12/13 =22.62º
There is no solution to given problem because you can't add a value 3/5 to angle 22.62º
(