SOLUTION: Let a, b, c, and dbe positive integers such that a < b < c < d.Suppose b = a + 2, c = a + 4, and d = a + 5. Write x^a + x^b + x^c + x^d in factored form.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Let a, b, c, and dbe positive integers such that a < b < c < d.Suppose b = a + 2, c = a + 4, and d = a + 5. Write x^a + x^b + x^c + x^d in factored form.      Log On


   



Question 513466: Let a, b, c, and dbe positive integers such that a < b < c < d.Suppose b = a + 2, c = a + 4, and d = a + 5. Write x^a + x^b + x^c + x^d in factored form.
Answer by drcole(72) About Me  (Show Source):
You can put this solution on YOUR website!
First, let's substitute in for b, c, and d, since we are given formulae for all three in terms of a:

Now let's remember how exponents add:
+x%5E%28p+%2B+q%29+=+x%5Ep+%2A+x%5Eq+
for all p and q. Thus we can rewrite our expression as:
+x%5Ea+%2B+x%5Ea+%2A+x%5E2+%2B+x%5Ea+%2A+x%5E4+%2B+x%5Ea+%2A+x%5E5+
Now let's look for ways to factor our expression. Notice that x^a is a common factor in each term, so we'll factor x^a out:
+x%5Ea+%2A+%281+%2B+x%5E2+%2B+x%5E4+%2B+x%5E5%29+
There doesn't appear to be any way to easily factor the remaining polynomial (the only possibilities for rational roots are 1 and -1, and neither of these work), so it looks like we're done.