SOLUTION: Michael rented a truck for one day. There was a rental fee of $20.99, and there also was a charge of 25 cents for each mile. Michael paid $95.74 when he returned the truck. For how

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Michael rented a truck for one day. There was a rental fee of $20.99, and there also was a charge of 25 cents for each mile. Michael paid $95.74 when he returned the truck. For how      Log On


   

Question 51329: Michael rented a truck for one day. There was a rental fee of $20.99, and there also was a charge of 25 cents for each mile. Michael paid $95.74 when he returned the truck. For how many miles did he drive the truck?

Found 2 solutions by rapaljer, Earlsdon:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = number of miles driven
Total charges: 20.99 +.25x = 95.74

Solve for x:
20.99 +.25x = 95.74
20.99 -20.99+.25x = 95.74-20.99
.25x = 74.75
%28.25x%29%2F.25+=+74.75%2F.25=299+miles.

R^2 at SCC

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Michael paid a total of $95.74 when he returned the truck. So, if we first deduct (subtract) the rental fee of $20.99 to see what he actually paid for mileage. Then we can divide the remainder by $0.25 to see how many miles he drove.
(Total cost - rental fee)/$0.25 = number of miles driven.
($95.74 - $20.99}/$0.25 = ($74.75)/$0.25 = 299
So Michael paid for 299 miles