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Question 51312: For the functions f(x) = 4x + 7 and g(x) = -9x + 11,
find f(g(0)).
For the functions f(x) = 3x2 - 7
and g(x) = -3x2 + 4,
find f(g(2)).
For the functions f(x) = 3x2 - 7
and g(x) = -3x2 + 8,
find g(f((-4)).
For the functions f(x) = 3x2 - 8
and g(x) = -7x2 + 5,
find g(f((-4)).
Answer by THANApHD(104)   (Show Source):
You can put this solution on YOUR website! ah composite functions! problems!
For the functions f(x) = 4x + 7 and g(x) = -9x + 11,
find f(g(0)).
f(g(x))= f(-9x+11) = 4(-9x+11)+7
= 4(-9*0+11)+7 (subtitute the values for ,0)
= 4*11+7
= 44+7
=51
For the functions f(x) = 3x2 - 7 ( actually wat U mean by 3x2,U mean 3(x^2) or (3x)^2)---and g(x) = -3x2 + 4,
find f(g(2)).
f(g(x))= f(-3x^2+4) = 3(-3x^2+4)^2-7
substiude x to 2=> = 3(-3(2^2)+4)^2-7
=3*(-8)^2-7
=3*64-7
=192-7
= 185
For the functions f(x) = 3x2 - 7
and g(x) = -3x2 + 8,
find g(f((-4)).
so f(g(x)) = 3{[-3(x^2)+8]^2}-7
x=(-)4=> 3(-40)^2-7
= 3*1600-7
=4800-7
= 4793
For the functions f(x) = 3x2 - 8
and g(x) = -7x2 + 5,
find g(f((-4)).
so f(g(x)) = 3{[-7(x^2)+5]^2}-8
x=(-4)=> 3{[-7((-4)^2)+5]^2}-8
= ??? You try it as the above
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