SOLUTION: the dimensions of a rectangle with a perimeter of 88 inches and the length one inch less than 4 times the width.

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Question 512875: the dimensions of a rectangle with a perimeter of 88 inches and the length one inch less than 4 times the width.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for perimeter:
+P+=+2W+%2B+2L+
given:
+2W+%2B+2L+=+88+
(1) +w+%2B+L++=+44+
also
(2) +L+=+4W+-+1+
---------------
(1) +L+=+44+-+W+
Substitute this into (2)
(2) +44+-+W+=+4W+-+1+
(2) +5W+=+44+%2B+1+
(2) +5W+=+45+
(2) +W+=+9+
and, since
(1) +L+=+44+-+W+
(1) +L+=+44+-+9+
(1) +L+=+35+
The dimensions are 9" x 35"
check:
+P+=+2W+%2B+2L+
+P+=+2%2A9+%2B+2%2A35+
+P+=+18+%2B+70+
+P+=+88+
OK