1st 2nd
n an differences differences
1 5 0 1
2 5 1 1
3 6 2 1
4 8 3 1
5 11 4
6 15
Since the 2nd differences are all constant we try a 2nd
degree polynomial in n
Simplifying:
Solve that system and get A = , B = , C = 6
So the equation
becomes:
Substituting n = 20
Substituting n = 21
Answers: ,
Edwin