Question 511715: A pilot flies 300km [E] and then 300km [W] at airspeed of 300km/h. A 30km/h wind is blowing to the east.
What is the pilot’s velocity relative to the ground for each leg of the trip?
What is the time for each leg of the trip, in minutes?
How long would the total trip take?
Answer by oberobic(2304)   (Show Source):
You can put this solution on YOUR website! The ground speed = air speed + or - the wind speed.
The wind is 30 km/h from west to east.
When the airplane is flying west, the wind is a headwind, reducing the ground speed.
When the airplane is flying east, the wind is a tailwind, increasing the ground speed.
d = r*t is the distance equation
d = 300 km
going west, ground speed = 300 km/h airspeed - 30 km/h headwind = 270 km/h
going east, ground speed = 300 km/h + 30 km/h tailwind = 330 km/h
Time (t) is the unknown.
d/r = t
.
Going east...
300/(300+30) = 300/330 = 30/33 =10/11 hr
10/11 hr * 60 min/hr = 600/11 min = approximately 54.54 min
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Going west...
300/(300-30) = 300/270 = 30/27 = 10/9 hr
10/9 hr * 60 min/hr = 600/9 = 200/3 = about 66.67 min
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Answer: The total trip takes 600/11 + 600/9 min, which equals approximately 121.21 min.
.
You can check the answer to determine the distances covered each way.
10/11 hr * 330 km/hr = 300 km
10/9 hr * 270 km/hr = 300 km
Correct
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Done.
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