Question 511618: Find all values of x in the interval [0, 2π] that satisfy the equation. (Enter your answers as a comma-separated list.)
6 sin2(x) = 3
Find all values of x in the interval [0, 2π] that satisfy the inequality. (Enter your answer using interval notation.)
3 sin(x) > 3 cos(x)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find all values of x in the interval [0, 2π] that satisfy the equation. (Enter your answers as a comma-separated list.)
6 sin2(x) = 3
Find all values of x in the interval [0, 2π] that satisfy the inequality. (Enter your answer using interval notation.)
3 sin(x) > 3 cos(x)
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6 sin2(x) = 3
sin^2(x)=3/6=1/2
Sin(x)=1/√2
x=(π/4, 3π/4) (in quadrants I and II where sin>0
..
3 sin(x) > 3 cos(x)
3 sin(x)/3 cos(x) >0
tan(x)>0
(0,π/2) U (π,3π/2) (in quadrants I and III where tan>0
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