SOLUTION: the length of a rectangle is twice as long as the width and its perimeter is 54 ft. find the dimensions of the rectangle. can you show me the steps.
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-> SOLUTION: the length of a rectangle is twice as long as the width and its perimeter is 54 ft. find the dimensions of the rectangle. can you show me the steps.
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Question 511552: the length of a rectangle is twice as long as the width and its perimeter is 54 ft. find the dimensions of the rectangle. can you show me the steps. Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! L = 2W
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P = 2(L+W)
P = 54
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substitute
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2(L+W) = 54
2(2W + W) = 54
4W +2W = 54
6W = 54
W = 9
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L = 2W
L = 2(9) = 18
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Check the perimeter
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2(18+9) = 2(27) = 54
Correct.
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Answer: Length = 18; Width = 9.
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Done.
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