SOLUTION: A radiator holds 16 quarts full of a solution with 30% alcohol. How much of this solution must be drawn off and replaced with pure alcohol in order that the contents of the radiato
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Question 511384: A radiator holds 16 quarts full of a solution with 30% alcohol. How much of this solution must be drawn off and replaced with pure alcohol in order that the contents of the radiator has 55% alcohol?
I really need to know both the solution and the answer, because I have a lot of other problems like this that are quite difficult... :S Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! ---------percent ---------------- quantity
Alcohol 100 ---------------- x quarts
Solution 30 ------ 16 - x quarts
Mixture 55.00% ---------------- 16
100 x + 30 ( 16 - x ) = 55 * 16
100 x + 480 - 30 x = 880
100 x - 30 x = 880 - 480
70 x = 400
/ 70
x=5.71 quarts 100.00% Alcohol
