SOLUTION: A man is 4 years older than his wife and 5 times as old as his son. When the son was born, the age of the wife was six-sevenths that of her husband's age. Find the age of each.

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Question 511377: A man is 4 years older than his wife and 5 times as old as his son. When the son was born, the age of the wife was six-sevenths that of her husband's age. Find the age of each.
Found 2 solutions by mananth, lwsshak3:
Answer by mananth(16946) (Show Source):
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Let wife's age be x
man's age = x+4
son's age = 1/5 * (x+4)
wife'a age when son was born : ( x- 1/5(x+4))
Husband's age when son was born ((x+4)-(1/5*(x+4))
6/7((x+4)-(1/5*(x+4))=( x- 1/5(x+4))
6/7(x+4 -((x+4)/5)) = (x-((x+4)/5))
LCD = 5
6/7(5x+20-x-4)/5 = (5x-x-4)/5
6/7(4x+16)/5 = 4x-4)/5
6/7(4x+16) = 4x-4
6(4x+16) = 7(4x-4)
24x+96=28x-28
4x=96+28
4x=124
x=31 Age of wife years
Age of Man = 31+4 = 35 years
Age of son = 1/5*35 =7 years.

Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
A man is 4 years older than his wife and 5 times as old as his son. When the son was born, the age of the wife was six-sevenths that of her husband's age. Find the age of each.
**
let x=wife's age
x+4=husband's age
(x+4)/5=son's age
..
x/(x+4)=6/7
7x=6x+24
x=24
x+4=28
(x+4)/5=28/5=5.6
ans:
wife's age=24
husband's age=28
son's age=5.6