SOLUTION: For all integers p and q, let # be defined by p # q = p^2 + q^2 + 2pq . Which of the following CANNOT be the value of p # q?
a.1
b.0
c.9
d.4
e.2
Algebra ->
Test
-> SOLUTION: For all integers p and q, let # be defined by p # q = p^2 + q^2 + 2pq . Which of the following CANNOT be the value of p # q?
a.1
b.0
c.9
d.4
e.2
Log On
Question 511345: For all integers p and q, let # be defined by p # q = p^2 + q^2 + 2pq . Which of the following CANNOT be the value of p # q?
a.1
b.0
c.9
d.4
e.2 Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! It is apparent that p # q = (p+q)^2. Since the function is only defined on integers p and q, the domain must be the perfect squares, so E)2 cannot be the value of p # q.