SOLUTION: Find the two solutions to this equation. ax^2+8ax=0

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Question 51108: Find the two solutions to this equation.
ax^2+8ax=0
Found 2 solutions by Earlsdon, Thanenjayan:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Find the two solutins:
ax%5E2%2B8ax+=+0 First, factor out an x.
x%28ax%2B8a%29+=+0 Apply the zero product principle.
x = 0 and/or ax+8a = 0
x = 0 is one of the two solutions.
ax%2B8a+=+0 Subtract 8a from both sides.
ax+=+-8a Divide both sides by a.
x+=+-8
x = -8 is the other solution.

Answer by Thanenjayan(7) About Me  (Show Source):
You can put this solution on YOUR website!
ax^2+8ax = 0
a (x^2+8x) = 0
x^2 + 8x = 0
x^2 + 8x + 16 = 16
(x+2)^2 = 16
x+2 = +or- 16^(1/2)

so
x+2 = + 4 or x+2 = -4
x = 2 or x = -2