SOLUTION: x^2+8x-y+6=0 Find the vertex, focus, and directrix of the parabola. Sketch the graph.

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Question 51091This question is from textbook college algebra
: x^2+8x-y+6=0
Find the vertex, focus, and directrix of the parabola. Sketch the graph. This question is from textbook college algebra

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 8x + 6 = y
v(-b/2a,f(x))
v(-8/2,f(x))
v(-4,-10)
~> p = 1/(4a)
~> p = 1/4 = 0.25
focus: (-4,-9.75)
directrix: y = -10.25
graph%28300%2C300%2C-12%2C12%2C-12%2C12%2Cx%5E2%2B8x%2B6%2C-10.25%29