SOLUTION: A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $560. How much did she invest at each rate?
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $560. How much did she invest at each rate?
Log On
Question 510903: A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $560. How much did she invest at each rate?
You can put this solution on YOUR website! A woman invested 4 times as much at 2% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $560. How much did she invest at each rate?
------------------------
Equations:
Quantity: x - 4y = 0
Interest:0.06x + 0.02y = 560
-------------------------------------
Multiply Quantity by 6
Multiply Interest by 100
6x - 24y = 0
6x + 2y = 56000
---
Subtract and solve for "y":
26y = 56000
y = $2153.85
----
Solve for "x":
x = $8115.39
------
Cheers,
Stan H.
=========================