SOLUTION: if you had 80 coins some of them are 1 dollar coins and the rest were 50 cent coins the total amount added up to 50 dollars how many coins of each kind were there?
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Question 510670: if you had 80 coins some of them are 1 dollar coins and the rest were 50 cent coins the total amount added up to 50 dollars how many coins of each kind were there? Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! Let x=number of 1 dollar coins
And y=number of 50 cent=1/2 dollar coins
so:
x*1+y*(1/2)=50 ---$ understood or
x+(1/2)y=50-----------------------------------eq1
and
x+y=80-----------------------------------------eq2
subtract eq1 from eq2
(1/2)y=30
y=60---------------------------number of 1/2 dollars
x=80-y=80-60=20-------------- number of dollars
CK
60*(1/2)+20*1=50
50=50
