SOLUTION: what is the equation of a line in standard form that passes through points (6,2) (9,10)

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Question 51058This question is from textbook algebra 2
: what is the equation of a line in standard form that passes through points (6,2) (9,10) This question is from textbook algebra 2

Answer by junior403(76) About Me  (Show Source):
You can put this solution on YOUR website!
What is the equation of a line in standard form that passes through points
(6,2) which we will call (x1,y1) and
(9,10)which we will call (x2,y2).
First we need to find the slope of the line using the solpe formula:
m+=+%28y2-y1%29%2F%28x2-x1%29
So we plug in our points.
m+=+%2810-2%29%2F%289-6%29
Then subtract
m+=+%288%29%2F%283%29
This is our slope.
Now we can use the point slope formula to get our equation.
y+-+y1+=+m+%28x+-+x1%29
Again lets plug in the variables.
y+-+2+=+%288%2F3%29+%28x+-+6%29
Now we can simplify by multiplying the entire equation by 3 to eliminate the fraction.
3%28y+-+2%29+=+3%288%2F3%29+%28x+-+6%29
3%28y+-+2%29+=+8+%28x+-+6%29
Then we can distribute both sides.
3y+-+6+=+8x+-+48
Now we can combine like terms.
add 6 to both sides...
3y+=+8x+-+42
this is simplified as far as possible, now we just need to put it into standard form: ax + by = c
So we can subtract the 8x from both sides...
-8x+%2B+3y+=+-42
then we should distribute the - through the equation which means that we should change the signs of ALL the variables.
8x+-3y+=+42
this is the final equation.
I hope this helps
Good Luck!