SOLUTION: the mean and standard deviation in a population are 4 and 0.2 resp.in a random sample of 400,how many are expected to have lengths greater than 4.4?
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Question 510579: the mean and standard deviation in a population are 4 and 0.2 resp.in a random sample of 400,how many are expected to have lengths greater than 4.4? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The mean and standard deviation in a population are 4 and 0.2 resp.
in a random sample of 400, how many are expected to have lengths greater than 4.4?
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z(4.4) = (4.4-4)/0.2 = 0.4/0.2 = 2
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P(x > 4.4) = P(z > 2) = 0.0228
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# of 400 that have length greater than 4.4 : 0.0228*400 = 9.1
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Cheers,
Stan H.
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