Question 510453: This is an age old problwm.
My mum was 27 when i was born. 8 Years ago she was twice as old as i shall be in 5 years, time. How old am i now
Found 2 solutions by Maths68, MathTherapy:
Answer by Maths68(1474)   (Show Source):
You can put this solution on YOUR website! Let
Present age of Mother = m
Present age of Son = s
Given
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When the son was born mother was 27, means mother is 27 older than son
m=s+27..............(1)
8 years ago means we have to subtract 8 from their present ages
m-8=s-8
then mother was twice as old as son will be in 5 means we have add 5 in the age of the son 8 years ago
(m-8)=2((s-8)+5)
m-8=2s-16+10
m-8=2s-6
m=2s-6+8
m=2s+2...........(2)
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Put the value of m from (1) to (2)
s+27=2s+2
s-2s=2-27
-s=-25
Multiply by (-1) both sides
-s(-1)=-25(-1)
s=25
Put the value of s in (1)
m=s+27
m=25+27
m=52
Present age of Mother = m = 52 years old
Present age of Son = s = 25 years old
Answer by MathTherapy(10849)  (Show Source):
You can put this solution on YOUR website!
This is an age old problwm.
My mum was 27 when i was born. 8 Years ago she was twice as old as i shall be in 5 years, time.
How old am i now
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I am NOT 25, as the other person states.
Let my age, be M
Then my mum is M + 27, since she was 27 when I was born
8 years ago, my mum was M + 27 - 8 = M + 19
In 5 years, I'll be M + 5
"8 Years ago she was twice as old as i shall be in 5 years, time," translates to: M + 19 = 2(M + 5)
M + 19 = 2M + 10
M - 2M = 10 - 19
- M = - 9
My age, or 
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