Question 510433: use factoring to solve the quadratic equation
x(x-2)^3 -35(x-2)^2=0 Found 2 solutions by mananth, lwsshak3:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! x(x-2)^3 -35(x-2)^2=0
(x-2)^2*(x(x-2)-35))
(x-2)^2*(x^2-2x-35)
(x-2)^2*(x^2-7x+5x-35)
(x-2)^2*(x(x-7)+5(x-7))
(x-2)^2*(x-7)(x+5)
You can put this solution on YOUR website! use factoring to solve the quadratic equation
x(x-2)^3 -35(x-2)^2=0
(x-2)^2[x(x-2)-35]=0
(x-2)^2=0
x=2 (multiplicity of 2)
..
[x(x-2)-35]=0
x^2-2x-35=0
(x-7)(x+5)=0
x-7=0
x=7
or
x+5=0
x=-5
ans:
zeros or roots are: -5, 2, 2, and 7
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