SOLUTION: How would I solve this logarithmic equation loga(x) + loga (x-2)= loga (x+4)
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Question 510308
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How would I solve this logarithmic equation
loga(x) + loga (x-2)= loga (x+4)
Answer by
edjones(8007)
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loga(x) + loga (x-2)= loga (x+4)
a^loga(x) * a^loga (x-2)= a^loga (x+4)
x(x-2)=x+4
x^2-2x-x-4=0
x^2-3x-4=0
(x-4)(x+1)=0
x=4
.
Ed